# The Pamphlet Collection of Sir Robert Stout: Volume 54

# The Problem of the Great Pyramid of Egypt

### The Problem of the Great Pyramid of Egypt

Is built up in the terms of the Inch, in the terms of π. In the Figure, the Circle represents the Period of the Perihelion, equal to 20,964 solar years, each year equal to 365.24 days. Its annual motion is equal to 11.63″ + 50.2″ equals 61.83″.

365.24 +&c × 2 : : 1 : π.

Arc AB is equal to 2739 years. Then, 2739 × 61.83″ ÷ 60 ÷ 60=47.067? equals Angle A *E* B=47° 4′ 0″.

Arc BC is equal to 7743 years. 7743 × 61.83″ ÷ 60 ÷ 60= 132.934° equals Angle B *E* C=132° 56′ 0″.

25,827 ÷ 7391.5x 1000=3494x6= 20,964 ÷ 2= 10,482 = the Period of the "Zone of water."

10,482-2739 = 7743. This, divided by 365.24 × π × 9 ÷ 2 ÷ 10=29.9706 equals 29° 58″ 14″ = the Latitude of the Great Pyramid in the terms of the Inch, in the terms of π.

π = Log. 0.497149, &c.

5813x2 = 11626 = the diameter of the Circle (as shown in the Figure) equals E E.

9131 in. × 4 ÷ 100 = 365.24.

In the Figure, aA = 375 years; add AE, 1369.5 years = 1744.5. This, multiplied by 61.83″ ÷ 60 ÷ 60 = 29° 58′ 9.44″. Latitude, by observation, equals 29° 58′ 51″ N.

The Foundation was laid 1744.5 years ± BF.

The Vertical height is in the terms of the Lesser distance of the Sun; therefore, 91,840,000 is equal to the Lesser distance ± (in inch miles).

51° 51′ 14″=51.8504+(61.83 x4) × π × 4 ÷ π × 625 = 20964 = the Circle.

Note.—The answers are to be read "symbolically" as equal to (in the terms of the Inch).

Reprinted from the Proceedings of the Royal Society.