The Pamphlet Collection of Sir Robert Stout: Volume 54

51 ÷ (652 ÷ 100) × π x7 ÷ l00 = 1.72018 1) I-1.7203 × (365.24 ÷ ?) }=652ins. II-One of the obtuse angles of these stones is equal to 128°, Then, 1284 ÷ (652 ÷ 10) × π ÷ 7 × 10 = 11.92143) 11.9223 × 7 ÷ 2 ÷ π × (5276 ÷ 100) } = 652in

51 ÷ (652 ÷ 100) × π x7 ÷ l00 = 1.72018 1) I-1.7203 × (365.24 ÷ ?) }=652ins. II-One of the obtuse angles of these stones is equal to 128°, Then, 1284 ÷ (652 ÷ 10) × π ÷ 7 × 10 = 11.92143) 11.9223 × 7 ÷ 2 ÷ π × (5276 ÷ 100) } = 652in.