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The Pamphlet Collection of Sir Robert Stout: Volume 54

I will now divide 5003 by the 35th and 36th courses— 5003 = 3.699231 35th Course = 35 = 1.544068 2.142928 π = 0.497149 449.07 = 2.652312 3592.56 × 10 = 35926 ± The first five figures of the mass of the sun as used in the Theory is ... ... ... ... ... ... = 35926 5003 = 3.699231 36th Course = 36 = 1.556303 2.142928 π=0.497149 436.59 = 2.640077 and 436.59 ÷ 10 = 43.7 (inch feet)

I will now divide 5003 by the 35th and 36th courses— 5003 = 3.699231 35th Course = 35 = 1.544068 2.142928 π = 0.497149 449.07 = 2.652312 3592.56 × 10 = 35926 ± The first five figures of the mass of the sun as used in the Theory is ... ... ... ... ... ... = 35926 5003 = 3.699231 36th Course = 36 = 1.556303 2.142928 π=0.497149 436.59 = 2.640077 and 436.59 ÷ 10 = 43.7 (inch feet)